Determining the Maximum Days Where Sam Sold More Bread Than Lucky
In this problem, we need to find the maximum number of days on which Sam sold more loaves of bread than Lucky.
Given:
- Sam sold 39 loaves of bread in 9 days.
- Lucky sold 54 loaves of bread in 9 days, at a rate of 6 loaves per day.
To solve this problem, we need to compare the daily sales of Sam and Lucky to determine the maximum number of days where Sam sold more loaves of bread.
Let's start by calculating the average daily sales for both Sam and Lucky:
Sam's average daily sales:
- Sam sold 39 loaves in 9 days
- Average daily sales = 39 loaves / 9 days = 4.33 loaves per day
Lucky's average daily sales:
- Lucky sold 54 loaves in 9 days
- Average daily sales = 54 loaves / 9 days = 6 loaves per day
Now, we can compare the daily sales of Sam and Lucky to find the maximum number of days where Sam sold more loaves of bread.
On any given day, if Sam's daily sales are greater than Lucky's daily sales, then Sam sold more loaves of bread than Lucky on that day.
To find the maximum number of days, we need to determine how many days Sam's daily sales were greater than Lucky's daily sales.
Since Sam's average daily sales are 4.33 loaves and Lucky's average daily sales are 6 loaves, we can see that Sam sold more loaves than Lucky on a maximum of 4 days.
This is because Sam's daily sales can only exceed Lucky's daily sales of 6 loaves on the days where Sam's daily sales are 6 loaves or more.
Therefore, the maximum number of days on which Sam sold more loaves of bread than Lucky is 4 days.