Calculating the HCl of a Solution: A Step-by-Step Guide

In this article, we will walk through the process of finding the HCl (Hydrochloric Acid) of a given volume and concentration of a solution, a common problem encountered in high school chemistry and mathematics.

The Problem

The problem is as follows: What is the HCl of 2.00 x 10^2 mL of 0.51 M (Molar) solution?

To solve this problem, we need to understand the concept of molarity and how to use it to calculate the amount of a solute in a solution.

Step 1: Understand Molarity

Molarity is a measure of the concentration of a solution, expressed as the number of moles of solute per liter of solution. The formula for molarity is:

Molarity (M) = Moles of solute / Volume of solution (in liters)

In this problem, the molarity of the solution is given as 0.51 M.

Step 2: Calculate the Moles of Solute

To find the moles of solute, we can rearrange the molarity formula:

Moles of solute = Molarity x Volume of solution (in liters)

Given:

• Molarity = 0.51 M
• Volume of solution = 2.00 x 10^2 mL = 0.200 L (since 1 L = 1000 mL)

Moles of solute = 0.51 M x 0.200 L = 0.102 moles

Step 3: Calculate the HCl

The HCl (Hydrochloric Acid) is the amount of hydrogen chloride (HCl) present in the solution. Since the molarity of the solution is given, we can directly use the moles of solute calculated in the previous step to find the HCl.

HCl = Moles of solute = 0.102 moles

Therefore, the HCl of 2.00 x 10^2 mL of 0.51 M solution is 0.102 moles.

In conclusion, by understanding the concept of molarity and applying the appropriate calculations, we can find the HCl of a given volume and concentration of a solution. This problem-solving skill is essential in high school chemistry and mathematics.