Determining the Maximum Days Where Sam Sold More Loaves of Bread Than Lucky

In this mathematical word problem, we need to find the maximum number of days where Sam sold more loaves of bread than Lucky.

Given the following information:

• Sam sold 39 loaves of bread in 9 days.
• Lucky sold 54 loaves of bread in 9 days, at a rate of 6 loaves per day.

To solve this problem, we need to calculate the daily sales for both Sam and Lucky, and then compare the two to find the maximum number of days where Sam sold more loaves.

Step 1: Calculate the daily sales for Sam

Sam sold 39 loaves of bread in 9 days, so his daily sales can be calculated as:

• Sam's daily sales = 39 loaves / 9 days = 4.33 loaves per day

Step 2: Calculate the daily sales for Lucky

Lucky sold 54 loaves of bread in 9 days, at a rate of 6 loaves per day, so his daily sales can be calculated as:

• Lucky's daily sales = 6 loaves per day

Step 3: Compare the daily sales and find the maximum number of days where Sam sold more

To find the maximum number of days where Sam sold more loaves than Lucky, we need to compare their daily sales for each day.

• Day 1: Sam's sales (4.33 loaves) < Lucky's sales (6 loaves)
• Day 2: Sam's sales (4.33 loaves) < Lucky's sales (6 loaves)
• Day 3: Sam's sales (4.33 loaves) < Lucky's sales (6 loaves)
• Day 4: Sam's sales (4.33 loaves) < Lucky's sales (6 loaves)
• Day 5: Sam's sales (4.33 loaves) < Lucky's sales (6 loaves)
• Day 6: Sam's sales (4.33 loaves) < Lucky's sales (6 loaves)
• Day 7: Sam's sales (4.33 loaves) < Lucky's sales (6 loaves)
• Day 8: Sam's sales (4.33 loaves) < Lucky's sales (6 loaves)
• Day 9: Sam's sales (4.33 loaves) < Lucky's sales (6 loaves)

Based on the comparison, we can see that Sam never sold more loaves of bread than Lucky on any of the 9 days. Therefore, the maximum number of days where Sam sold more loaves than Lucky is 0 days.